Organic Chemistry · Part 9 of 9

Functional-Group Interconversions, Heterocycle Syntheses & Multicomponent Reactions

Named Reactions, Part 9 · 22 sections · about 14,068 words · CSIR-NET Chemical Sciences, GATE Chemistry & IIT-JAM

The final part gathers the reactions that swap one functional group for another, that build rings containing nitrogen, oxygen and sulfur, and that assemble a complex product from three or four simple pieces in one pot. Three families in one file. Functional-group interconversions: make ethers (Williamson), primary amines cleanly (Gabriel, Delépine), alkenes by anti elimination (Hofmann, with the Hofmann-vs-Zaitsev orientation rule), interconvert halides (Finkelstein, Appel), remove a carbon as CO₂ (Hunsdiecker), invert an alcohol while substituting it (Mitsunobu), turn a nitrile + carbocation into an amide (Ritter), N-methylate or reductively aminate (Eschweiler–Clarke, Leuckart), make esters at equilibrium (Fischer), and build α-amino acids (Strecker). Heterocycle syntheses: indoles (Fischer), furans/pyrroles/thiophenes (Paal–Knorr), pyrroles (Knorr), dihydropyridines/pyridines (Hantzsch), quinolines (Skraup, Doebner–Miller), iso- and tetrahydroisoquinolines (Bischler–Napieralski, Pictet–Spengler), and dihydropyrimidinones (Biginelli). Multicomponent: the Ugi (4-component) and Passerini (3-component) isocyanide reactions. Two layers on every reaction: a hand-held beginner path (plain “what it does”, RDKit scheme, arrow-by-arrow mechanism, graded worked examples, trap boxes) and a research-grade advanced/reference path (mechanism & stereoelectronics, regio- and chemoselectivity, scope & FG-tolerance tables, variants, selectivity comparisons, research-level problems). The file closes with a Book master index of all nine parts.

The 22 sections in Part 9

  • 1The Williamson ether synthesis Free below
  • 2The Gabriel synthesis (& the Delépine variant)
  • 3The Hofmann elimination (& Hofmann vs Zaitsev)
  • 4The Finkelstein reaction (halide exchange)
  • 5The Appel reaction (alcohol → halide)
  • 6The Hunsdiecker reaction (RCOOAg → R–Br)
  • 7The Mitsunobu reaction (alcohol + acidic Nu, inversion)
  • 8The Ritter reaction (nitrile + carbocation → amide)
  • 9Reductive amination: Eschweiler–Clarke & Leuckart–Wallach
  • 10The Fischer esterification (acid + alcohol ⇌ ester)
  • 11The Strecker amino-acid synthesis
  • 12The Fischer indole synthesis
  • 13The Paal–Knorr synthesis (furan / pyrrole / thiophene)
  • 14The Knorr pyrrole synthesis
  • 15The Hantzsch dihydropyridine / pyridine synthesis
  • 16The Skraup & Doebner–Miller quinoline syntheses
  • 17Bischler–Napieralski & Pictet–Spengler (isoquinolines)
  • 18The Biginelli dihydropyrimidinone synthesis
  • 19The Passerini reaction (3-component)
  • 20The Ugi reaction (4-component)
  • 21The nine parts at a glance
  • 22What Part 9 (this file) contains

The Williamson ether synthesis

Free extract

Section AA.1 of Part 9, reproduced in full from the book — figures and all. No sign-in, no paywall on this section.

SN2alkoxide + R–Xethers1° halide onlyepoxides (intramolecular)
Beginner layer

An alkoxide (or phenoxide) attacks a primary alkyl halide from the back, kicks out the halide, and the two oxygens-and-carbons become an ether. The single most general way to make an ether with a chosen pair of groups.

In one line: deprotonate an alcohol to its alkoxide (R–O⁻), then let it do an SN2 on a primary alkyl halide (or tosylate) R′–X to give the ether R–O–R′. Because it is SN2, the halide-bearing carbon must be unhindered (methyl or primary).

Prototype Williamson: sodium ethoxide + bromoethane → diethyl ether. The alkoxide oxygen displaces bromide in one backside step.

The alcohol is first converted to its conjugate base with NaH, Na metal, or K₂CO₃ (for phenols); the alkoxide is the real nucleophile.

Mechanism — Williamson (SN2 at the halide carbon)
  1. Deprotonation: R–OH + NaH → R–O⁻ Na⁺ + H₂ (alkoxide formed).
  2. Backside attack: the alkoxide oxygen attacks the primary carbon of R′–X from the side opposite X; a pentacoordinate SN2 transition state forms.
  3. Leaving-group loss & inversion: X⁻ departs, the new C–O bond forms, and configuration at that carbon inverts (if it was a stereocentre) → ether R–O–R′.

How would you make tert-butyl methyl ether (MTBE) by Williamson? Which pairing works? Medium

There are two conceivable pairings: (a) tert-butoxide + CH₃I, or (b) methoxide + tert-butyl bromide.
The SN2 carbon must be unhindered. In (a) the electrophilic carbon is methyl (perfect SN2); in (b) it is tertiary (SN2 impossible → E2 gives isobutylene).
So use potassium tert-butoxide + methyl iodide. Always put the leaving group on the less-hindered partner.

Predict the product of treating a 1,2-halohydrin (2-chloroethanol, deprotonated) with base. Easy

Base deprotonates the –OH to an alkoxide on the carbon beta to the C–Cl.
The alkoxide does an intramolecular SN2 on the neighbouring C–Cl (3-membered ring closure).
Product: ethylene oxide (an epoxide) — the intramolecular Williamson is the standard epoxide synthesis from halohydrins.

⚠ Common mistakes & exam traps

  • Use a primary (or methyl) halide. Secondary is sluggish; tertiary halides eliminate (E2) with the basic alkoxide instead of substituting.
  • Symmetry trap. For an unsymmetrical ether there are two disconnections — always choose the one that puts X on the unhindered carbon.
  • Phenyl ethers: aryl halides do not do SN2; make aryl alkyl ethers by alkylating a phenoxide (ArO⁻ + R–X), not by using Ar–X.
  • Elimination side-reaction. Hindered alkoxides (KOtBu) are strong bases — keep the electrophile primary to avoid E2.
Advanced / reference layer

SN2 stereoelectronics and the epoxide (intramolecular) case, alternatives for aryl and hindered ethers (Ullmann, Cu, Ag₂O, Mitsunobu), and use in protecting-group chemistry.

Stereoelectronics and the intramolecular (epoxide) variant

Williamson is a textbook SN2: rate = k[RO⁻][R′X], backside attack, inversion at the electrophilic carbon, and a reactivity order CH₃ > 1° > 2° >> 3° (3° does not react by SN2). Intramolecular versions are governed by Baldwin's rules: 3-exo-tet (halohydrin → epoxide) and 5-exo-tet ring closures are fast and favoured; 4-exo and 6-endo are slower. The epoxide route is stereospecific — an anti-halohydrin gives a defined epoxide diastereomer.

ElectrophileWilliamson outcomeReason / fix
CH₃X, 1° R–Xclean etherideal SN2
2° R–Xmoderate yield, some alkeneslower SN2; competing E2
3° R–Xmostly alkene (E2)put LG on the other partner
Ar–Xno reaction (SN2)use ArO⁻ + R–X, or Cu/Ullmann, or SNAr
halohydrin (intramol.)epoxide (3-exo-tet)stereospecific; needs anti geometry
SN2 substrate scope of the Williamson synthesis.

Alternatives for the cases Williamson cannot do

For diaryl ethers and hindered aryl alkyl ethers, use Ullmann-type copper catalysis or modern Cu/Pd C–O couplings (see Part 8). Silver(I) oxide promotes selective O-alkylation (useful in carbohydrate chemistry, where it favours mono-etherification of a chosen –OH). The Mitsunobu reaction (this Part, AA.5) couples an alcohol directly with an acidic pronucleophile (including phenols) with inversion — effectively a Williamson that uses R–OH instead of R–X and avoids strong base.

Med
Why does using sodium phenoxide + iodomethane give anisole cleanly, whereas bromobenzene + sodium methoxide gives essentially no anisole?
Show solution
Anisole (PhOMe) requires forming the O–CH₃ bond. With PhO⁻ + CH₃I, the SN2 electrophile is a methyl carbon — fast, clean. With PhBr + CH₃O⁻, the electrophile would be an aryl carbon, which cannot undergo SN2 (backside attack is blocked by the ring; no accessible σ* aligned) and lacks activation for SNAr. Hence only the phenoxide route works.
Hard
An (R)-2-bromobutane reacts with sodium methoxide to give a chiral methyl ether. Predict the stereochemistry.
Show solution
SN2 proceeds with inversion at C2. (R)-2-bromobutane → the ether with inverted configuration at that carbon (formally (S) if priorities are unchanged; check CIP priorities after swapping Br for OMe). Some E2 (2-butene) will accompany it because the substrate is secondary and methoxide is basic.
Hard
Which diastereomer of 3-bromobutan-2-ol gives trans-2,3-epoxybutane — and why is there no meso 3-bromobutan-2-ol?
Show solution
First, the meso point. 3-Bromobutan-2-ol (CH₃CH(OH)CH(Br)CH₃) has no meso form: C2 carries –OH and C3 carries –Br, so the two stereocentres bear different substituent sets and no internal mirror plane can relate them. Its four stereoisomers are two pairs of enantiomers — (2R,3R)/(2S,3S) and (2R,3S)/(2S,3R). (The meso compound in this story is the cis-epoxide, not the halohydrin.)
Then the closure. Deprotonate the –OH; the alkoxide performs an intramolecular 3-exo-tet SN2 on the adjacent C–Br, with inversion at C3 (the carbon that loses bromide) and retention at C2 (its bonds are never broken). Only the conformer with O and Br anti-periplanar can close, so the halohydrin's relative configuration fixes cis vs trans.
Answer: start from the (2R,3S) (or its enantiomer (2S,3R)) diastereomer. C2 stays R and C3 inverts S → R, giving (2R,3R)-2,3-epoxybutane — the chiral trans-epoxide. The other diastereomer, (2R,3R) (or (2S,3S)), closes to the (2R,3S) = meso = cis-epoxide.

Further reading.

  • Named for Alexander William Williamson, who reported the alkoxide + alkyl halide ether synthesis in the mid-19th century (c. 1850).
  • Baldwin, J. E. ‘Rules for Ring Closure’, J. Chem. Soc., Chem. Commun. 1976, 734–736.

Read the rest of Part 9

The remaining 21 sections of this part — The Gabriel synthesis (& the Delépine variant), The Hofmann elimination (& Hofmann vs Zaitsev), The Finkelstein reaction (halide exchange), The Appel reaction (alcohol → halide) — and all nine parts of Named Reactions are part of ChemVidya Full Access, along with the other books, 55 Study Notes and 6,000+ practice questions.

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