Deep-Dive Guides · Ionic Equilibria

Ionic Equilibria & Buffers — the complete deep dive

One guide dense enough to take you from "pH = −log[H⁺]" to CSIR-NET Part-C fluency. The organising idea: aqueous ionic equilibria are just equilibrium constants applied to protons and ions in water, held together by three conservation laws — mass balance, charge balance, and the water autoionisation Kw.

Free extract — the opening section of the guide, in full.

0. How to use this guide — the master map ▲ top

Every pH or solubility problem is solved by imposing the same three conservation laws on the relevant equilibrium constants. Fix the map first:

SituationGoverning relationFast result
Strong acid/basefull dissociationpH = −log cacid (or 14 + log cbase)
Weak acid HAKa = [H⁺][A⁻]/[HA][H⁺] ≈ √(Kac)
Weak base BKb = [BH⁺][OH⁻]/[B][OH⁻] ≈ √(Kbc)
Buffer (HA + A⁻)Henderson–HasselbalchpH = pKa + log([A⁻]/[HA])
Salt of weak acidhydrolysis Kh = Kw/Kabasic; pH > 7
Sparingly soluble saltKsp = ∏[ion](coefficient)s from Ksp; common-ion suppresses
Always true (the relation; not the value)Kw = [H⁺][OH⁻], which is 1.0×10⁻¹⁴ at 25 °C onlypH + pOH = pKw = 14.00 at 25 °C
The three master equations behind everything: (1) Mass balance — total analytical concentration is conserved across all species. (2) Charge balance — solution is electrically neutral: Σ(cation charge) = Σ(anion charge). (3) Kw — water is always in equilibrium. Every "shortcut" formula below is one of these three plus an approximation.

Constants (25 °C): Kw = 1.0 × 10⁻¹⁴, so pKw = 14.00 and pH + pOH = 14.00. For any conjugate pair, Ka·Kb = Kw, i.e. pKa + pKb = 14.00. Reference weak-acid data used here: acetic acid Ka = 1.8 × 10⁻⁵ (pKa = 4.74); ammonia Kb = 1.8 × 10⁻⁵ (pKb = 4.74, so pKa of NH₄⁺ = 9.26).

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The remaining 9 sections — Water, pH and weak acids/bases, Buffers, Acid–base titrations & indicators, Solubility equilibria & Ksp and more — are part of ChemVidya Full Access, along with the other guides, the books, the study notes and 6,000+ practice questions with worked solutions.

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