Inorganic · Coordination Chemistry

Crystal Field Theory (CFT)

CSIR-NET Chemical Sciences revision note · 9 sections · about 548 words · free to read in full

Exam-focused revision notes on Crystal Field Theory (CFT) for CSIR-NET Chemical Sciences, GATE Chemistry and IIT-JAM — the core concepts, the formulas worth memorising, the traps that cost marks, and a quick-recall table.

The core idea

A metal ion's five d orbitals are degenerate when free. Surround it with ligands and their lone pairs repel the d electrons — but unequally, because some d orbitals point at the ligands and some point between them. That unequal repulsion splits the d orbitals in energy. The pattern depends on geometry.

Octahedral field (most important)

  • Ligands approach along the x, y, z axes.
  • Orbitals pointing at the ligands — dz², dx²−y² — are raised: the eg set (higher).
  • Orbitals pointing between — dxy, dxz, dyz — are lowered: the t2g set (lower).
  • Energy gap = Δo (octahedral splitting).
  • Barycentre rule: t2g at −0.4 Δo, eg at +0.6 Δo.

CFSE (crystal field stabilization energy)

CFSE = [−0.4 × n(t2g) + 0.6 × n(eg)] Δo + (pairing-energy terms)

Read it straight off the electron count. Example: low-spin d6 = t2g6eg0 → CFSE = 6(−0.4) = −2.4 Δo (plus pairing) — very stable, which is why [Co(NH3)6]3+ is inert.

High-spin vs low-spin (exam favourite)

  • Compare Δo with the pairing energy P.
  • Δo < P → electrons spread out first (Hund) → high-spin (weak-field ligands).
  • Δo > P → electrons pair in t2g first → low-spin (strong-field ligands).
  • Only d4–d7 octahedral can be high- or low-spin; d1–d3 and d8–d10 have only one option.

Spectrochemical series

Weak field → strong field:

I− < Br− < Cl− < F− < OH− < H2O < NH3 < en < NO2− < CN− ≈ CO

Left = small Δo, high-spin. Right = large Δo, low-spin. CN−, CO, NO2− are strong-field π-acceptors.

Tetrahedral field

  • Δt ≈ (4/9) Δo — always small → tetrahedral complexes are almost always high-spin.
  • Splitting is inverted: e (lower) below t2 (higher).

What CFT explains (and gets asked)

  • Magnetic moment: μ = √(n(n+2)) BM (n = unpaired e−). High-spin d5 = 5.92 BM; low-spin d6 = 0 (diamagnetic).
  • Colour: d–d transitions absorb light of energy ≈ Δo; the complementary colour is seen. Larger Δo → absorbs shorter λ.
  • Stability / CFSE trends and Jahn–Teller distortion (uneven eg occupancy, e.g. d9 Cu2+).

⚠️ Common traps students miss

  • Tetrahedral is e below t2 (opposite of octahedral) — easy to flip and lose the mark.
  • For tetrahedral, strong-field ligand ≠ low-spin (Δt too small — usually high-spin regardless).
  • CFSE alone doesn't decide spin state — you compare Δ with P.
  • The observed colour is the complement of what's absorbed.

30-second recall table

d-countOct high-spin (unpaired e−)Oct low-spin (unpaired e−)
d442
d551
d640
d731

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